Your vessel displaces 12,000 tons and has a...

Study

Question 1 of 2066636eec28f7522a1c51d0eb

Your vessel displaces 12,000 tons and has a KG of 22.6 feet. What will be the length of the remaining righting arm at an angle of inclination of 30? if the center of gravity shifts 1.8 feet transversely? (Use the information in Section 1, the blue pages, of the Stability Data Reference Book)

Back

Question 1 of 20

66636eec28f7522a1c51d0eb

No comments yet

Be the first to share your thoughts!

If the question has a related picture, it will appear here.

🔍 Key Concepts

• Transverse shift of G creates a heeling arm (GZₕ) that reduces the effective righting arm at a given angle • Use the Stability Data Reference Book (Section 1, blue pages) to obtain the original GZ at 30° for the given KG • Compute the horizontal shift of G due to a known transverse shift and then compare it with the original righting arm at 30°

💭 Think About

• From the blue pages, find the uncorrected righting arm (GZ) at 30° for KG = 22.6 ft. How does this value change when G moves transversely? • How do you convert a 1.8‑ft transverse shift of G into a heeling lever at 30°? (Think about the relationship between the shift, the displacement, and the sine of the angle.) • Once you have the heeling lever caused by the shift of G, how do you combine it with the original GZ to obtain the remaining effective righting arm?

✅ Before You Answer

• Be sure you are using the correct GZ value at 30° from the blue pages for KG = 22.6 ft • Confirm your units are consistent (feet for arms, tons for displacement if needed in intermediate steps) • After adjusting GZ for the heeling effect, check that the resulting righting arm is smaller than the original GZ at 30° (because shifting G transversely reduces stability at that angle)

👋 Hi! I'm Genie, your AI study assistant. How can I help you with this question?

Quick actions

— No credit card needed