Your vessel displaces 10,000 tons and has a...

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Question 1 of 2066636eec28f7522a1c51d0ea

Your vessel displaces 10,000 tons and has a KG of 22.6 feet. What will be the length of the remaining righting arm at an angle of inclination of 45? if the center of gravity shifts 2.0 feet transversely? (Use the information in Section 1, the blue pages, of the Stability Data Reference Book)

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Question 1 of 20

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🔍 Key Concepts

• Use the KN-curves and the formula relating GZ, KN, KG, and heel angle from the blue pages • Effect of a transverse shift of G (GG₁) on the righting arm at a given angle • Difference between the righting arm (GZ) and a heeling arm created by G moving off the centerline

💭 Think About

• From the blue pages, identify which table/curve you use at 45° and how you combine KN and KG to get the original righting arm (before G shifts) • Think about what happens when the center of gravity moves 2.0 feet off the centerline: does this create a new lever that tends to heel the ship or to right it? How do you combine that with the original GZ? • At 45°, which trig function goes with vertical component of KG and which goes with the horizontal shift GG₁? Make sure you don’t mix up sin and cos for the two effects.

✅ Before You Answer

• From the blue pages, write down the correct KN value at 45° and use the proper formula to compute the initial GZ at 45° using KG = 22.6 ft • Confirm that the given 2.0 ft is the distance GG₁ (already the shift of G), so you do not need to compute it from displacement and a shifted weight • Before picking an answer, compute both the original GZ at 45° and the heeling arm from GG₁ at 45° and then combine them (righting minus heeling) to get the remaining righting arm. Check that your final number is close to one of the choices.

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