You have 240 tons of below deck tonnage....

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Question 1 of 2066636eec28f7522a1c51beea

You have 240 tons of below deck tonnage. There is no liquid mud aboard. If you have 360 tons of cargo above deck with a VCG above the deck of 2.9 feet, what is the maximum allowed VCG of the remainder of the deck cargo that is permitted? See illustration D036DG below.

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Question 1 of 20

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🔍 Key Concepts

• Use the loading diagram D036DG to find the maximum total above‑deck cargo allowed when below‑deck tonnage is 240 long tons. • Apply the combined VCG (vertical center of gravity) formula: total VCG is a weight‑weighted average of each cargo group’s VCG. • Remember the note on the diagram: maximum deck‑cargo VCG = 3.0 ft above deck for the total deck load, not for each piece separately.

💭 Think About

• First, from the graph, what is the maximum allowed total deck cargo (in tons) when the below‑deck tonnage is exactly 240 long tons? • If 360 tons of deck cargo already has a VCG of 2.9 ft, how can you express the overall deck‑cargo VCG using 360 tons, the unknown remainder, and their individual VCGs? • Set the overall deck‑cargo VCG equal to the 3.0‑ft limit and solve for the VCG of the remainder. Which option matches that result?

✅ Before You Answer

• Be sure you are reading the correct curve on the diagram (safe/unsafe boundary) and using long tons on both axes. • Confirm that your total deck‑cargo VCG is computed as ( \text{VCG}_{total} = \frac{\sum (w_i \times \text{VCG}_i)}{\sum w_i} ). • After solving, check that the resulting VCG is physically reasonable (not higher than the 3.0‑ft limit for the combined load and consistent with the multiple‑choice options).

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