You are on course 079°T, speed 11.2 knots....

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Question 1 of 2066636ee928f7522a1c51945d

You are on course 079°T, speed 11.2 knots. At 0904 you see a daymark bearing 078°T at a range of 4.6. If you change course at 0910 to leave the daymark abeam to starboard at 0.5 mile, at what time will the daymark be abeam?

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Question 1 of 20

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🔍 Key Concepts

• Relative bearings and “abeam to starboard” – what true bearing will the daymark have when it is exactly abeam on your starboard side? • Advancing your position – how far do you travel between 0904 and 0910 at 11.2 knots, and where does that put you relative to the daymark? • Time–speed–distance – once you know the distance from your 0910 position to the abeam point, how do you convert that distance to time at 11.2 knots?

💭 Think About

• From 0904 to 0910, compute the distance run along 079°T. How does that change your range and bearing to the daymark at 0910? • At 0910, you choose a new course so that your track passes 0.5 NM on the starboard side of the daymark. On your plotting sheet, what does that track line look like in relation to the daymark? • Once you identify on the plot where the vessel will be when the daymark is abeam to starboard at 0.5 NM, how do you determine how long it takes to get from the 0910 position to that abeam point at 11.2 knots?

✅ Before You Answer

• Be sure you correctly compute the distance run in 6 minutes at 11.2 knots using ( D = S \times T ). • Confirm that your plotted abeam position has the daymark exactly 90° on your starboard side and at 0.5 NM range. • After measuring the track distance from your 0910 position to the abeam point, double-check your time calculation using ( T = \frac{D}{S} ) and add it correctly to 0910 before picking a choice.

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