What would be the voltage across a 50-ohm...

Question 1 / 27070cvs9zCx3wkdHajUmoTrh

Question 1 of 27070cvs9zCx3wkdHajUmoTrh

What would be the voltage across a 50-ohm dummy load dissipating 1,200 watts?

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Question 1 of 27070

Q

What would be the voltage across a 50-ohm dummy load dissipating 1,200 watts?

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🔍 Key Concepts

• Relationship between power (P), voltage (V), and resistance (R) in a purely resistive circuit • Using the correct power formula: ( P = \frac{V^2}{R} ) and how to solve it for V • What a dummy load is (a resistor that converts electrical power into heat, with no reactance)

💭 Think About

• Which formula directly links power, voltage, and resistance without involving current? • If ( P = \frac{V^2}{R} ), how can you rearrange this to solve for V in terms of P and R? • After calculating the voltage, which of the multiple-choice answers is numerically closest to your result?

✅ Before You Answer

• Be sure you use ohms (Ω) for resistance, watts (W) for power, and you end up with volts (V) for voltage. • Carefully compute ( V = \sqrt{P \times R} ) and double-check the square root step. • Verify that your final voltage value, when put back into ( P = \frac{V^2}{R} ), gives you about 1,200 W.

Question 1 of 27070

Q

What would be the voltage across a 50-ohm dummy load dissipating 1,200 watts?

A

245 volts.

B

692 volts.

C

346 volts.

D

173 volts.

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Question 1 / 27070cvs9zCx3wkdHajUmoTrh

Question 1 of 27070cvs9zCx3wkdHajUmoTrh

What would be the voltage across a 50-ohm dummy load dissipating 1,200 watts?

Back

Question 1 of 27070

Q

What would be the voltage across a 50-ohm dummy load dissipating 1,200 watts?

If the question has a related picture, it will appear here.

🔍 Key Concepts

• Relationship between power (P), voltage (V), and resistance (R) in a purely resistive circuit • Using the correct power formula: ( P = \frac{V^2}{R} ) and how to solve it for V • What a dummy load is (a resistor that converts electrical power into heat, with no reactance)

💭 Think About

• Which formula directly links power, voltage, and resistance without involving current? • If ( P = \frac{V^2}{R} ), how can you rearrange this to solve for V in terms of P and R? • After calculating the voltage, which of the multiple-choice answers is numerically closest to your result?

✅ Before You Answer

• Be sure you use ohms (Ω) for resistance, watts (W) for power, and you end up with volts (V) for voltage. • Carefully compute ( V = \sqrt{P \times R} ) and double-check the square root step. • Verify that your final voltage value, when put back into ( P = \frac{V^2}{R} ), gives you about 1,200 W.