What was the current between 0615 and 0650...

Question 1 of 2707066636eea28f7522a1c51b035

What was the current between 0615 and 0650 if you were steering 240°pgc and your speed through the water was 14.5 knots?

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Question 1 of 27070

What was the current between 0615 and 0650 if you were steering 240°pgc and your speed through the water was 14.5 knots?

🔍 Key Concepts

• Vector triangle of course steered, track made good, and current • Difference between speed through the water and speed made good over the ground • Current set (direction toward) and drift (speed)

💭 Think About

• Is your actual track over the ground to the left or right of your steered course of 240°pgc? That tells you which general quadrant the current set must be in. • Compare distance run by log (through the water) with distance made good over the ground for this time interval. Is the current helping or opposing your motion? • Once you sketch the vector triangle, which combination of direction (035°T vs 075°T) and speed (2 vs 3 knots) best closes the triangle to match the observed ground track?

✅ Before You Answer

• Be clear which line is course and speed through the water and which line is track and speed over the ground on your plot. • Make sure the current vector is drawn from the end of the water-track vector to the end of the ground-track vector (water to ground). • Check that your chosen set (°T) matches the direction toward which the current must flow to shift your water track onto the observed ground track.