Using a safety factor of 6, determine the...

Question 1 / 2707066636ee728f7522a1c518e76

Question 1 of 2707066636ee728f7522a1c518e76

Using a safety factor of 6, determine the safe working load of a line with a breaking strain of 30,000 pounds.

Back

Question 1 of 27070

Q

Using a safety factor of 6, determine the safe working load of a line with a breaking strain of 30,000 pounds.

🔍 Key Concepts

• Safe working load (SWL) versus breaking strain (ultimate strength) • How to apply a safety factor to reduce the maximum allowed load • Basic division of large numbers and checking whether the result is reasonable

💭 Think About

• Should a safety factor make the allowed working load larger or smaller than the breaking strain? By how much? • What mathematical operation (multiplication or division) correctly applies a safety factor of 6 to a breaking strain of 30,000 lbs? • Once you calculate the SWL, which answer choice is closest to that value and still matches your exact calculation?

✅ Before You Answer

• Confirm that SWL must always be less than the breaking strain when a safety factor greater than 1 is used • Carefully compute 30,000 divided by 6 and double-check the arithmetic • Eliminate any options that are greater than 30,000 lbs or clearly do not match your computed value

Question 1 of 27070

Q

Using a safety factor of 6, determine the safe working load of a line with a breaking strain of 30,000 pounds.

A

100,000 lbs.

B

20,000 lbs.

C

5,000 lbs.

D

4,000 lbs.

Question 1 / 2707066636ee728f7522a1c518e76

Question 1 of 2707066636ee728f7522a1c518e76

Using a safety factor of 6, determine the safe working load of a line with a breaking strain of 30,000 pounds.

Back

Question 1 of 27070

Q

Using a safety factor of 6, determine the safe working load of a line with a breaking strain of 30,000 pounds.

🔍 Key Concepts

• Safe working load (SWL) versus breaking strain (ultimate strength) • How to apply a safety factor to reduce the maximum allowed load • Basic division of large numbers and checking whether the result is reasonable

💭 Think About

• Should a safety factor make the allowed working load larger or smaller than the breaking strain? By how much? • What mathematical operation (multiplication or division) correctly applies a safety factor of 6 to a breaking strain of 30,000 lbs? • Once you calculate the SWL, which answer choice is closest to that value and still matches your exact calculation?

✅ Before You Answer

• Confirm that SWL must always be less than the breaking strain when a safety factor greater than 1 is used • Carefully compute 30,000 divided by 6 and double-check the arithmetic • Eliminate any options that are greater than 30,000 lbs or clearly do not match your computed value