The longitudinal free surface moments of a...

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Question 1 of 2066636ef128f7522a1c522708

The longitudinal free surface moments of a drilling mud pit aboard a MODU displacing 24,000 long tons in sea water is 1,200 ft-long tons. If the sounding level in the mud pit is reduced from 8 to 6 feet and the mud weight increases from 10 to 12 lbs/gallon, what is the new FSML for the mud pit?

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🔍 Key Concepts

• Remember that free surface moment in a slack tank is related to the area of the free surface, not the volume below it. • Consider what changes when the mud level drops in a rectangular pit: does the free surface area change, or just the depth? • Think about how a change in mud weight (density) from 10 to 12 lb/gal affects the free surface moment, if all other geometry stays the same.

💭 Think About

• Ask yourself: for a rectangular mud pit that is still slack, does reducing the sounding from 8 ft to 6 ft change the size of the free surface, or only how much mud is in the tank? • How is free surface moment affected by a change in liquid density? Is it directly proportional, inversely proportional, or unaffected? • Can you express the new free surface moment as the original FSML multiplied by a simple ratio based on the change in mud weight?

✅ Before You Answer

• Verify whether tank geometry (length and breadth of the free surface) has changed when the level drops from 8 ft to 6 ft. • Confirm how density ratio (12 ÷ 10) would scale the original FSML if geometry and ship displacement stay constant. • Before picking an answer, check if you are incorrectly using volume or depth instead of free surface area in your reasoning.

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