The following questions are based on Chart...

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Question 1 of 2066636ee928f7522a1c5197af

The following questions are based on Chart 12221TR, Chesapeake Bay Entrance, and the supporting publications. Your present course is 202°T and your vessel's engines are turning RPMs for 18 knots. Your height of eye is 54 feet (16.5 meters) and your vessel's draft is 28 feet (8.5 meters). Use 10°W variation where required. At 0800 your position is LAT 37°21.0'N, LONG 75°32.0'W. Assuming that there is no set and drift, what time would your vessel cross the 60-foot curve?

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Question 1 of 20

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🔍 Key Concepts

• Using the 60-foot depth curve on Chart 12221TR relative to your track line • Applying the speed–distance–time relationship at 18 knots • Projecting your course of 202°T from the given 0800 position to find a future point on the chart

💭 Think About

• From your 0800 position, carefully plot your 202°T course line and mark where it intersects the 60-foot curve. How far is that point from your 0800 position in nautical miles? • Once you know the distance to the 60-foot curve, how many minutes will it take to travel that distance at 18 knots (think nm per minute)? • After you get the running time in minutes, what is the resulting time when you add it to 0800?

✅ Before You Answer

• Confirm you are using true course (202°T) directly with the chart, not converting to magnetic for the plot. • Double-check the distance measurement along your course line specifically to the 60-foot curve (not another depth contour). • Verify your speed conversion to nm per minute (knots to minutes), and that you add the time to 0800 correctly.

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