The COASTAL DRILLER, with no trim, is at a...

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Question 1 of 2066636ee728f7522a1c517764

The COASTAL DRILLER, with no trim, is at a true mean draft of 10 feet and 10 inches. TM is -6,800 ft-kips. Using only tanks 1, 25, and 26, how many kips of drill water must be transferred to level the jack-up?

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Question 1 of 20

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🔍 Key Concepts

• Trim moment (TM) and how moving weight creates a trimming moment: ( M = w \times d ) • Difference between longitudinal and transverse weight shifts (what affects trim vs list) • Using the distance between tank centers (LCGs) when calculating the moment from a transfer

💭 Think About

• Look at where tanks 1, 25, and 26 are located longitudinally. Which moves actually shift weight forward or aft, and which just move it side‑to‑side? • For each answer choice, what total trimming moment (in ft‑kips) does the proposed transfer create relative to the reference point? Compare this to the given TM of -6,800 ft‑kips. • Consider the direction of the moment: does the proposed transfer create a moment that opposes the existing TM (tending to level the jack‑up), or one that makes it worse?

✅ Before You Answer

• From the vessel’s plan, confirm the longitudinal distances (in feet) between the centers of tanks 1, 25, and 26. • For each option, compute total moment: weight moved (kips) × longitudinal distance (ft) between the tanks involved; be sure to include the sign (forward vs aft). • Check whether any option that moves water only between tanks 25 and 26 actually changes the longitudinal center of gravity or just the transverse position. Only a change in LCG will correct trim.

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