The COASTAL DRILLER, with no list, is at a...

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Question 1 of 2066636ee728f7522a1c51772a

The COASTAL DRILLER, with no list, is at a true mean draft of 10 feet and 10 inches. LM is 1,699,463 ft-kips. Using only tanks 1, 25, and 26, how many kips of drill water must be transferred to level the jack-up?

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Question 1 of 20

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🔍 Key Concepts

• Longitudinal moments (LM) and how they relate to trim and weight shifts • Effect of transferring weight forward vs. aft on bow and stern drafts • How using two aft tanks (25 & 26) versus one forward tank (1) changes the total trimming moment

💭 Think About

• First, think about what it means that the jack-up is already at a true mean draft of 10 ft 10 in with no list. Does that automatically mean the vessel is on an even keel (no trim)? • Consider what happens to longitudinal trim when you move drill water from a forward tank to aft tanks, and vice versa. Which direction of transfer would reduce any existing trim? • Compare the magnitude of weight transfers in each option and how they would affect the total trimming moment using the given LM value. Which option seems more consistent with making only the correction needed to level the jack-up?

✅ Before You Answer

• Verify whether the given LM (1,699,463 ft-kips) is used to relate a required change in trimming moment to a needed weight shift (Moment = Weight × Distance). • Check which option preserves total weight (no loading/discharging), involving only internal transfer of drill water. • Confirm which option creates a trimming moment in the direction needed to correct any initial trim, based on whether the bow or stern would be deeper.

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