The barge shown in the illustration is 40' X...

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Question 1 of 205eccef9dbacbc34ba4d45e0d

The barge shown in the illustration is 40' X 20' X 10' and weighs 22.9 long tons when empty. The theoretical maximum amount of machinery and cargo which may be installed or loaded is __________. See illustration GS-0157.

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🔍 Key Concepts

• Displacement of a box-shaped barge (volume of underwater body × weight of 1 cubic foot of water) • Using full dimensions (L × B × H) of the barge to find the maximum possible underwater volume • Subtracting lightship weight (22.9 long tons) from the total displacement to get maximum cargo/machinery

💭 Think About

• If the barge were submerged right up to the deck edge (full 10-foot depth), what would be the total underwater volume in cubic feet? • Using the standard exam conversion for salt water, how many cubic feet of seawater equal 1 long ton, and how do you use that to turn volume into tons? • Once you know the total possible displacement at that immersion, how do you account for the fact that the barge itself already weighs 22.9 long tons?

✅ Before You Answer

• Make sure you use all three dimensions (40' × 20' × 10') when finding volume, not just L × B. • Use the correct saltwater conversion: cubic feet per long ton, not short ton. • After finding total displacement, subtract 22.9 long tons to get the theoretical maximum machinery and cargo capacity.

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