On 5 June your 0420 zone time DR position is...

Study

Question 1 of 2066636eea28f7522a1c51ae24

On 5 June your 0420 zone time DR position is LAT 26°47.0' N, LONG 133°19.5' W. At that time, you observe Vega bearing 298.1°psc. The chronometer reads 01h 21m 17s, and the chronometer error is 02m 25s fast. The variation is 3.5°E. What is the deviation of the standard compass?

Back

Question 1 of 20

66636eea28f7522a1c51ae24

No comments yet

Be the first to share your thoughts!

If the question has a related picture, it will appear here.

🔍 Key Concepts

• Converting chronometer time to GMT (UT1), paying attention to a chronometer that is fast • How to find a star’s true azimuth (Zn) from DR position, GHA, and declination using sight reduction methods or tables • The relationship between true bearing, variation, magnetic bearing, and compass bearing (psc) to solve for deviation

💭 Think About

• After correcting the chronometer, what is the actual GMT of the sight, and what is the corresponding LHA for Vega at your DR position? • Once you have the true azimuth of Vega, how do you convert that true bearing step-by-step to the bearing you would expect on the standard compass if there were no deviation? • Given the observed standard compass bearing and your computed magnetic bearing, what must the deviation be, and is it east or west?

✅ Before You Answer

• Be sure you apply chronometer error in the correct direction for a fast chronometer before entering the Nautical Almanac • Double-check the sign of longitude (west) when forming LHA and that you are using the correct variation 3.5°E in the right direction • Carefully apply the compass error chain (e.g., True–Variation–Magnetic–Deviation–Compass) so the sign of deviation (E or W) matches the way the compass reading differs from magnetic

👋 Hi! I'm Genie, your AI study assistant. How can I help you with this question?

Quick actions

— No credit card needed