On 28 September in DR position LAT...

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Question 1 of 2066636eea28f7522a1c51add4

On 28 September in DR position LAT 24°12.0'S, LONG 85°25.0'E, you observe an amplitude of the Sun. The Sun's center is on the visible horizon and bears 094°psc. The chronometer reads 11h 29m 42s and is 03m 30s slow. Variation in the area is 4°W. What is the deviation of the magnetic compass?

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Question 1 of 20

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🔍 Key Concepts

• Amplitude of the Sun at rising/setting and how it relates to true bearing • Relationship between true bearing, variation, magnetic bearing, and compass bearing • How declination and latitude determine whether the Sun is north or south of East at sunrise

💭 Think About

• Think about whether you really need the exact time, or whether amplitude at the visible horizon depends mainly on the Sun’s declination and your latitude. • Use the amplitude formula to find the true amplitude, then convert that to a true bearing of the Sun on the horizon. • Once you have the true bearing, apply the given variation to get a magnetic bearing, then compare with the observed compass bearing (psc) to determine the deviation and its east/west name.

✅ Before You Answer

• Be sure you are using the correct signs for latitude and declination (North/South) in the amplitude calculation. • Check that you are applying variation with the correct sign: “4°W” means what happens to go from true to magnetic? • When comparing compass and magnetic bearings, confirm which way you go from one to the other to decide whether the deviation is east or west.

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