On 26 January your 1615 ZT DR position is...

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Question 1 of 2066636eea28f7522a1c51ada7

On 26 January your 1615 ZT DR position is LAT 27° 14.0' S, LONG 57° 22.0' W. At that time, you observe the Sun bearing 266° psc. The chronometer reads 08h 13m 19s, and the chronometer error is 01m 46s slow. The variation is 4° E. What is the deviation of the standard magnetic compass?

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Question 1 of 20

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🔍 Key Concepts

• True bearing vs. compass bearing and how to get from one to the other using variation and deviation • How to correct chronometer time using chronometer error, then find GHA and declination for the Sun at the sight time • Relationship: Compass → Magnetic → True (and reverse), using "deviation" and "variation"

💭 Think About

• How do you turn the observed Sun bearing (given in points/psc) into a compass bearing in degrees? • Once you find the true bearing of the Sun from your DR position and time, how do you compare it with the compass bearing to solve for deviation? • Are you applying the signs of variation (E/W) and deviation (E/W) correctly when going between Compass, Magnetic, and True?

✅ Before You Answer

• Convert the Sun’s 266° psc bearing to a compass bearing in degrees before doing anything else • Carefully compute UTC/GMT from the given ZT and chronometer data before entering the Nautical Almanac (or sight reduction tables) • When you compare true and compass bearings, double‑check the direction (E or W) of the resulting deviation before choosing the answer

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