On 23 August in DR position LAT 24°07.0'N,...

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Question 1 of 2066636eea28f7522a1c51ad54

On 23 August in DR position LAT 24°07.0'N, LONG 136°16.0'E, you observe an amplitude of the Sun. The Sun's center is on the visible horizon and bears 074.5°psc. The chronometer reads 08h 56m 19s and is 02m 34s fast. Variation in the area is 2°W. What is the deviation of the magnetic compass?

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🔍 Key Concepts

• Amplitude of the Sun and how to use date and DR longitude to find the Sun’s declination and true amplitude • Converting a psc (per ship’s compass) bearing to magnetic and then to true (or vice versa) using variation and deviation • The relationship: Variation + Deviation = Compass Error (east/west sign convention)

💭 Think About

• From the DR position and date, what is the approximate Sun’s declination, and is the Sun rising or setting based on the bearing? • How do you convert the observed compass bearing of the Sun on the visible horizon into a true bearing using the amplitude method? • Once you know the true bearing and compare it to the compass bearing, what does the difference tell you about total compass error, and how do you separate variation and deviation?

✅ Before You Answer

• Be clear on the sign convention: whether easterly errors/variations/deviations are taken as plus or minus in your method • Confirm whether the Sun’s observed amplitude corresponds to a rising or setting Sun for the hemisphere and bearing you have • After finding total compass error, carefully apply the known variation (2°W) to isolate the deviation and check that your final sign (E or W) is consistent with your earlier steps

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