On 22 February your 0612 zone time fix gives...

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Question 1 of 2066636eea28f7522a1c51ace6

On 22 February your 0612 zone time fix gives you a position of LAT 27°16.2'S, LONG 37°41.6'W. Your vessel is on course 298°T, and your speed is 14.2 knots. Local apparent noon (LAN) occurs at 1147 zone time, at which time a meridian altitude of the Sun's lower limb is observed. The observed altitude (Ho) for this sight is 73°33.3'. What is the calculated latitude at LAN?

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🔍 Key Concepts

• Meridian passage (LAN) sight reduction for latitude using the Sun • Running a DR (dead reckoning) position from a morning fix to the time of LAN • Relationship between Ho, Dec, and Lat when observing the Sun on your meridian

💭 Think About

• From 0612 to 1147, how much time elapses, and what distance do you travel at 14.2 knots along course 298°T? • Once you have your DR latitude at LAN time, how do you combine the Sun’s declination and your measured Ho to find latitude on a meridian passage? • On 22 February, is the Sun’s declination north or south, and is the Sun north or south of your zenith for this sight?

✅ Before You Answer

• Compute the run: time difference in hours × 14.2 kn, then resolve this run along N–S and E–W components for the 298°T course • Confirm from the Nautical Almanac whether the Sun’s declination on 22 February at LAN is north or south and its approximate value • Apply the correct meridian altitude formula for latitude, paying attention to whether the Sun and observer are in the same or opposite hemispheres and whether you must add or subtract the zenith distance and declination

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