On 17 November in DR position LAT 01°14.4'S,...

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Question 1 of 2066636eea28f7522a1c51ab59

On 17 November in DR position LAT 01°14.4'S, LONG 148°45.5'E, you take an ex-meridian observation of the planet Venus at upper transit. The chronometer time of the sight is 05h 31m 42s, and the chronometer error is 01m 50s fast. The sextant altitude (hs) is 64°41.1'. The index error is 1.8' off the arc, and your height of eye is 50 feet. What is the latitude at meridian transit?

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Question 1 of 20

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🔍 Key Concepts

• Ex-meridian sight of a body near upper transit and how it approximates a meridian altitude • Relationship between Ho, declination, and latitude at meridian passage • Sign rules when the body’s declination and your latitude are same name vs contrary name

💭 Think About

• After applying all corrections to get Ho, how would the true meridian altitude at upper transit relate to Ho if the sight was taken slightly before/after the meridian? • Once you know (or approximate) the meridian altitude, how do you combine it with the planet’s declination to find latitude, and which sign (N/S) applies? • Given your DR latitude and the fact that Venus is near the meridian, should you expect the final latitude to be very different from the DR, or only slightly different?

✅ Before You Answer

• Be sure you’ve correctly corrected chronometer time with the error (fast/slow) before entering the Nautical Almanac tables • Confirm you applied all altitude corrections: index correction sign (off the arc), dip for 50 ft, and standard refraction, etc., to get Ho • Check whether the declination and latitude are same name or contrary name, and whether your formula for latitude matches that case before you compare to the choices

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