On 14 January your 0746 zone time DR...

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Question 1 of 2066636eea28f7522a1c51aaba

On 14 January your 0746 zone time DR position is LAT 26°37.0'N, LONG 153°19.0'W. At that time, you observe the Sun bearing 123°psc. The chronometer reads 05h 49m 16s, and the chronometer error is 02m 29s fast. The variation is 3°W. What is the deviation of the standard magnetic compass?

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Question 1 of 20

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🔍 Key Concepts

• Using the Sun’s observed bearing to find compass error (difference between true and compass directions) • Converting chronometer time to Zone Time and then to Greenwich Hour Angle (GHA) and declination for the Sun • Relationship between variation, deviation, and compass error: True, Magnetic, Compass (T–V–M–D–C)

💭 Think About

• From the DR position, date, and corrected chronometer time, what is the Sun’s true bearing at that moment? • How do you convert the compass bearing of the Sun (psc) to a true bearing, step by step, using variation and an unknown deviation? • Once you know the true bearing and the compass bearing, how can you express compass error and then separate it into variation and deviation to solve for deviation and its east/west sign?

✅ Before You Answer

• Be sure you apply the chronometer error correctly (it is given as fast, not slow) before entering the Nautical Almanac tables • Keep track of whether you are working west longitude and how that affects GHA and LHA (Local Hour Angle) calculations • When you set up T–V–M–D–C, keep the sign convention consistent so that if the compass reads higher or lower than true, you assign east or west correctly to the deviation

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