On 12 September your 0736 zone time DR...

Study

Question 1 of 2066636eea28f7522a1c51aa6c

On 12 September your 0736 zone time DR position is LAT 28°34.0'S, LONG 174°49.0'E. At that time, you observe the Sun bearing 084° per standard magnetic compass (psc). The chronometer reads 07h 38m 11s, and the chronometer error is 01m 46s fast. The variation is 11°W. What is the deviation of the standard magnetic compass?

Back

Question 1 of 20

66636eea28f7522a1c51aa6c

No comments yet

Be the first to share your thoughts!

If the question has a related picture, it will appear here.

🔍 Key Concepts

• True bearing vs. compass bearing – relationship between true, magnetic, and compass (T–V–M–D–C) • Chronometer correction – using chronometer error (fast/slow) to find correct UTC at the time of observation • Sun azimuth (Zn) – using the DR position, date, and time to find the true bearing of the Sun

💭 Think About

• First, correct the chronometer time using the given chronometer error, then convert to the correct UTC/GMT time for the sight • From the DR position, date, and correct time, determine the true azimuth (Zn) of the Sun and compare it to the observed psc bearing • Convert the observed psc to compass bearing, then step through T–V–M–D–C (or your preferred sequence) to isolate the deviation

✅ Before You Answer

• Be sure the chronometer error (fast vs. slow) is applied in the correct direction when finding the actual time • Double‑check the sign of variation (11°W) and how it affects the step from True to Magnetic • When you compare the calculated compass bearing with the observed compass bearing, verify whether the resulting deviation should be labeled East or West

👋 Hi! I'm Genie, your AI study assistant. How can I help you with this question?

Quick actions

— No credit card needed