In a simple saturated cycle, an R-134a...

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Question 1 of 205eccef9dbacbc34ba4d45f65

In a simple saturated cycle, an R-134a refrigeration system has a high side pressure of 123.58 psig and a low side pressure of 1.9334 psig. Using this information and the data shown in the illustration, determine the refrigeration effect per pound of refrigerant circulated, neglecting any subcooling or superheating effects. See illustration GS-RA-23.

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🔍 Key Concepts

• Use the saturated R-134a property table to match each given pressure to its corresponding saturation temperature and enthalpies. • In a simple saturated refrigeration cycle, the refrigeration effect per pound is the difference in enthalpy of saturated vapor leaving the evaporator and enthalpy of saturated liquid entering the evaporator. • Remember that psig must be converted to psia before you match the given pressures to the table values.

💭 Think About

• Which column in the table corresponds to the enthalpy of saturated liquid at the condenser pressure, and which column to the enthalpy of saturated vapor at the evaporator pressure? • Once you find the two enthalpy values that match the high‑side and low‑side pressures, what single subtraction gives you the refrigeration effect in BTU/lb? • How close do the table pressures (psia) need to be to your converted system pressures (psia) for a typical exam problem—exact match or closest reasonable value?

✅ Before You Answer

• Convert psig to psia by adding atmospheric pressure (about 14.7 psi) before using the table. • Be sure you are reading the correct phase: liquid enthalpy for the condenser outlet and vapor enthalpy for the evaporator outlet. • After subtraction, check that your result is in BTU/lb and compare it to the multiple‑choice options to find the closest match.

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