How is the power dissipated as heat in a...

Question 1 / 2707066636eed28f7522a1c51d8dc

Question 1 of 2707066636eed28f7522a1c51d8dc

How is the power dissipated as heat in a simple direct current circuit consisting of one resistive load calculated?

Question 1 of 27070

How is the power dissipated as heat in a simple direct current circuit consisting of one resistive load calculated?

🔍 Key Concepts

• Ohm's Law relationships between voltage (E), current (I), and resistance (R) • Basic power formulas for DC circuits (P = EI, P = I²R, P = E²/R) • Units check: power in watts, current in amperes, resistance in ohms

💭 Think About

• Start from the basic power formula P = EI. If you only know current and resistance in a simple resistive DC circuit, how can you use Ohm's Law (E = IR) to rewrite P in terms of I and R only? • Look at each choice and ask: does this expression have the correct units for power (watts)? For example, what are the units of I²R? Of E/I? Of P/R? • Which formula shows power as something that increases quickly as current goes up, matching the idea that too much current overheats wires?

✅ Before You Answer

• Confirm which expression actually equals power (P) using Ohm's Law substitutions, not one that equals voltage or current. • Check that the final units work out to watts (W), not volts or amps. • Remember that in a purely resistive DC circuit, all electrical power is converted to heat in the resistor.

Question 1 of 27070

How is the power dissipated as heat in a simple direct current circuit consisting of one resistive load calculated?

E/I

P/R

I2R

(IR)/T