Halving the cross-sectional area of a...

Question 1 of 29218yvKJ6edu6KmMbAwWVtVP

Halving the cross-sectional area of a conductor will:

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Question 1 of 29218

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Halving the cross-sectional area of a conductor will:

🔍 Key Concepts

• Ohm’s Law and how resistance relates to voltage and current • The formula for resistance of a conductor: R = ρ·L / A (where ρ is resistivity, L is length, A is cross‑sectional area) • How changing only the area (while keeping length and material the same) affects resistance

💭 Think About

• If the area is cut in half but length and material stay the same, what happens to the value of R in the formula R = ρ·L / A? • Is resistance directly proportional or inversely proportional to cross‑sectional area? How does that relationship change R when A becomes A/2? • Compare the new resistance R_new to the old resistance R_old as a ratio (R_new / R_old). What numerical factor do you get?

✅ Before You Answer

• Be sure you treat area correctly in the formula (don’t confuse it with length). • Confirm that material (ρ) and length (L) are assumed constant, so the only changing term is A. • Verify, using the ratio R_new / R_old, whether the resistance becomes larger or smaller, and by what factor.