For an analog electronic transmission system...

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Question 1 of 205eccefa5bacbc34ba4d487a7

For an analog electronic transmission system for instrumentation purposes, if an electronic level indicator has a calibrated scale of 0 to 1800 mm, what would be the actual measured liquid level of the tank if the transmitted signal current is 12 mA, assuming the industry standard of 4 to 20 mA is used for instrument current?

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🔍 Key Concepts

• 4–20 mA standard where 4 mA = 0% and 20 mA = 100% of the measuring range • How to find the percentage of span for a given current between 4 and 20 mA • How to convert a percentage of span into a level in millimeters when the range is 0–1800 mm

💭 Think About

• What fraction of the 4–20 mA span does a 12 mA signal represent? (Think: how far is 12 mA between 4 and 20?) • Once you know the percentage of span, how do you apply that to the 0–1800 mm scale to get the level? • Is any offset needed at 0 mA, or does the span start at 4 mA for 0 level?

✅ Before You Answer

• First compute span current: 20 mA − 4 mA, and use that as your denominator • Calculate (measured current − 4 mA) ÷ span current to get the fraction of full scale • Multiply that fraction by 1800 mm and compare your result to the choices

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