At 2326 ZT on 22 June, your vessel's...

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Question 1 of 2066636eea28f7522a1c51ad73

At 2326 ZT on 22 June, your vessel's position is LAT 28° 30' N, LONG 150° 04' W. An azimuth of the planet Jupiter is observed, and the standard compass bearing is 250.4°. The chronometer reads 09h 24m 36s and is 01m 12s slow. The variation of this area is 13.5° E. What is the deviation of the standard compass?

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🔍 Key Concepts

• Using a celestial azimuth (true bearing of Jupiter) to determine compass error • The TVMDC relationship: True, Variation, Magnetic, Deviation, Compass • Rules for east/west signs when applying variation and deviation

💭 Think About

• First, think about how you will get the true azimuth (Zn) of Jupiter at the given time and position. What steps and tables or formulas are usually involved? • Once you have the true bearing, how do you compare it with the standard compass bearing to find total compass error? Which direction (east or west) is the compass in error? • After finding total compass error, how do you separate it into variation and deviation using the given local variation?

✅ Before You Answer

• Confirm you have converted the chronometer time to UT correctly, including the sign of the chronometer error (slow vs fast). • Verify that you applied variation with the correct sign: "East is least, West is best" when going from True to Magnetic. • Check whether the compass is clockwise or counterclockwise from the true bearing. That will tell you if the total compass error (and then the deviation) is east or west.

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