At 2232 ZT on 14 July you are in DR position...

Study

Question 1 of 2066636eea28f7522a1c51ad40

At 2232 ZT on 14 July you are in DR position LAT 33° 52' S, LONG 150° 03' W, when you observe an amplitude of Jupiter. The planet is about one Sun's diameter above the visible horizon and bears 268.5° pgc. The variation is 15° E. What is the gyro error?

Back

Question 1 of 20

66636eea28f7522a1c51ad40

No comments yet

Be the first to share your thoughts!

If the question has a related picture, it will appear here.

🔍 Key Concepts

• Amplitude of a celestial body near the horizon and how it relates to true bearing • Using declination and latitude to compute amplitude • Relationship between true bearing, variation, and gyro bearing (pgc) to find gyro error

💭 Think About

• How do you compute the true amplitude of a body at the visible horizon from its declination and your DR latitude? • Once you have the amplitude, how do you turn that into a true bearing for a body setting in the western horizon? • After finding the true bearing, how do you compare it with the observed pgc bearing and use the given variation to decide the size and EAST/WEST sense of the gyro error?

✅ Before You Answer

• Be sure you are using the correct sign for latitude and declination (N/S) in the amplitude formula. • Confirm you are using the west-setting formula for converting amplitude to true bearing (since the body bears about 268.5°). • Check the gyro error convention you are using: is it "gyro least, error east" or "true – gyro"? Make sure the sign you assign (E or W) matches your comparison.

👋 Hi! I'm Genie, your AI study assistant. How can I help you with this question?

Quick actions

— No credit card needed