At 150 degrees, what is the amplitude of a...

Question 1 / 27070UiRp5wwATiNgWvPWNKSY

Question 1 of 27070UiRp5wwATiNgWvPWNKSY

At 150 degrees, what is the amplitude of a sine-wave having a peak value of 5 volts?

Question 1 of 27070

At 150 degrees, what is the amplitude of a sine-wave having a peak value of 5 volts?

🔍 Key Concepts

• Sine function values at key angles (0°, 30°, 45°, 60°, 90°, and related angles in other quadrants) • Relationship between peak value and instantaneous value: $v = V_{peak} \cdot \sin(\theta)$ • Signs of sine in different quadrants of the unit circle (I, II, III, IV)

💭 Think About

• First determine which quadrant 150° is in and whether sine is positive or negative there. • Think of 150° in terms of its related acute angle (e.g., 180° - ?). What is the sine of that related angle? • Once you know $\sin(150°)$ , multiply it by the peak value (5 volts) to find the instantaneous voltage.

✅ Before You Answer

• Confirm whether 150° is in a quadrant where sine is positive or negative. • Verify the exact value of $\sin(150°)$ using its reference angle. • After multiplying by 5 volts, check which option matches both the magnitude and the sign of your result.