As shown in the illustration, what happens...

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Question 1 of 205eccefa4bacbc34ba4d4845a

As shown in the illustration, what happens when the main feed switch is closed, the change-over switch for the masthead light is in position "2" and the masthead light "2" burns out? See illustration EL-0058.

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🔍 Key Concepts

• Study how the change-over transfer switch selects either lamp 1 or lamp 2 in the "two-compartment running light" section. • Trace the current path from the supply bus, through the selected masthead lamp, and through the trouble relay coil and alarm light in the "typical navigation light circuit". • Think about what happens to current flow, the relay, and the buzzer when a lamp burns out (opens the circuit) compared with when a fuse blows (overcurrent).

💭 Think About

• With the change-over switch in position "2", which physical lamp actually has current flowing when the system is healthy? What happens to that current path if that lamp filament goes open-circuit? • Is the trouble relay coil designed to be energized during normal operation or when there is a fault? How does that choice affect whether the buzzer and trouble lamp get power when the bulb fails? • Would a lamp simply burning out cause more current (blowing a fuse) or no current in that branch of the circuit? How does that help you rule out some answer choices?

✅ Before You Answer

• Verify on the diagram which side of the lamps and relay are tied to the supply bus and which to the buzzer bus. • Check the dashed connection between the trouble relay and alarm light to see what changes when the relay coil is de‑energized versus energized. • Confirm that a burned‑out lamp is an open circuit, while a blown fuse is a response to excess current—use this to eliminate any answer that doesn’t match the expected current condition.

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