As shown in the illustration of a vessels...

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Question 1 of 2066636eed28f7522a1c51db92

As shown in the illustration of a vessels navigational lighting circuit, if port running light "1" burns out, the trouble buzzer will sound and the port running light trouble lamp will illuminate. Switching to port running light "2" clears the alarm. If port running light "1" is replaced with a light of a smaller wattage and the circuit is switched back to port running light "1", which of the following is true? Illustration EL-0058

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Question 1 of 20

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🔍 Key Concepts

• Review how wattage, voltage, current, and resistance are related by Ohm’s law for a lamp at a fixed supply voltage. • Look closely at the diagram to see whether the trouble relay coil is in series with, or parallel to, the running light it monitors. • Consider what happens to current through the relay coil if the lamp in that branch is replaced by one with higher resistance (lower wattage) at the same voltage.

💭 Think About

• If the supply voltage stays the same but you install a lamp of lower wattage, what happens to the circuit current compared with the original lamp? • In this monitoring design, does the relay need more current or less current to energize and open its alarm contacts? How would reduced current affect the alarm state? • Which options are logically inconsistent with the electrical behavior you’d expect when current is reduced in this branch of the circuit?

✅ Before You Answer

• Verify from the schematic whether the relay coil and the running light share the same current path (i.e., are effectively in series). • Compute or qualitatively compare the current draw of the original lamp vs. the lower‑wattage lamp at the same voltage to see which is larger. • Check each choice against the idea that a lower‑wattage lamp means less current in that branch, not more, and see which statements are compatible with that.

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