As shown in the illustration, a section of...

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Question 1 of 205eccef9abacbc34ba4d450c0

As shown in the illustration, a section of standard weight, seamless steel pipe, has an external diameter of 3.5 inches. When the pipe is bent into a 90° turn, the length of the outside edge of the curve "A-B" will exceed the length of the inside edge of the curve "C-D" by __________. See illustration GS-0108.

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🔍 Key Concepts

• Relationship between arc length, radius, and central angle in radians • How the outside radius and inside radius of a bent pipe** differ** when the pipe’s outside diameter is known • Converting degrees to radians for a 90° bend

💭 Think About

• Imagine the pipe’s centerline is bent into a quarter of a circle. How far is the outside surface from the centerline compared to the inside surface? • If the bend angle is the same for both A-B and C-D, which quantity actually controls the difference in arc lengths: the bend radius, the angle, or the pipe diameter? • Write a formula for the arc length of A-B and C-D, then subtract them. What cancels out?

✅ Before You Answer

• Be sure to convert the 90° bend into radians before using the arc length formula • Confirm that the difference between the outside and inside radii equals the given pipe diameter (3.5 inches), not some fraction of it • After computing, compare your numerical result to the choices and check that your units are inches

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