As shown in figure "B" of the illustration,...

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Question 1 of 205eccefa4bacbc34ba4d483b7

As shown in figure "B" of the illustration, due to the effect of distributed capacitance, what would be the voltage of each bus phase with respect to the common equipment grounding conductor (hull ground)? See illustration EL-0126.

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🔍 Key Concepts

• 480 VAC 3-phase system: difference between line-to-line voltage and line-to-ground (line-to-neutral) voltage • In figure B, the three phase conductors each have equal distributed capacitance to the hull, forming a kind of balanced wye connection to ground • For a balanced 3‑phase system, the relationship between line voltage and phase (line‑to‑neutral) voltage is V_line = √3 × V_phase

💭 Think About

• In figure B, with no ground fault shown, where is the "neutral point" of the three equal capacitors to ground located with respect to the three phase voltages? • If the system line-to-line voltage is 480 VAC, what is the corresponding line-to-neutral (phase) voltage found by dividing by √3? • Which answer choice most closely matches the line-to-ground voltage you would expect in a balanced, ungrounded 480 V 3‑phase system where capacitance to ground is equal on all three phases?

✅ Before You Answer

• Confirm that the source in figure B is labeled "480 VAC 3‑Phase Source" • Confirm that no solid connection to ground is shown in figure B—only capacitive paths from each phase to the hull (common equipment-grounding conductor) • Before choosing, calculate V_phase = V_line / √3 for a 480 V system and compare that value to the answer choices

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