A vessel displaces 12,000 tons and has a KG...

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Question 1 of 2066636eec28f7522a1c51d0ec

A vessel displaces 12,000 tons and has a KG of 22.8 feet. What will be the length of the remaining righting arm at an angle of inclination of 60? if the center of gravity shifts 1.8 feet transversely? (Use the information in Section 1, the blue pages, of the Stability Data Reference Book)

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Question 1 of 20

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🔍 Key Concepts

• Transverse shift of G and how it creates a heeling arm (GG₁) • How to get GZ at 60° from the Stability Data Reference Book before the shift of G • How the new righting arm at 60° is found by combining original GZ and the heeling arm due to the shift

💭 Think About

• First, using 12,000 tons and KG 22.8 ft, what GZ value does the blue pages give you at 60° before any shift? • How does a 1.8-ft transverse shift of G create a heeling lever at 60°? Think about the relationship between GG₁ and the sine or cosine of the heel angle. • Once you know the original GZ and the heeling arm, how do you combine them (add or subtract?) to get the remaining righting arm at 60°?

✅ Before You Answer

• Make sure you read the correct GZ(60°) from the blue pages using the given displacement and KG. • Check that you convert the 1.8-ft shift of G into a heeling lever using the proper trigonometric function for 60°. Don’t skip this step. • Before choosing an answer, decide if the remaining righting arm should be positive or negative at 60°. That will help you eliminate some options.

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