A tank 36 ft. by 36 ft. by 6 ft. is filled...

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Question 1 of 2066636eec28f7522a1c51ce7b

A tank 36 ft. by 36 ft. by 6 ft. is filled with water to a depth of 5 ft. If a bulkhead is placed in the center of the tank running fore-and-aft along the 36-foot axis, how will the value of the moment of inertia of the free surface be affected?

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Question 1 of 20

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🔍 Key Concepts

• Free surface moment of inertia of a rectangular tank about the ship’s centerline • How moment of inertia changes when you change the breadth (width) of the free surface • Effect of dividing one wide tank into two narrower tanks side‑by‑side

💭 Think About

• First, write the formula for the free surface moment of inertia of a single rectangular tank about the ship’s centerline in terms of breadth (B) and length (L). Which dimension is raised to the 3rd power? • Next, recalculate the moment of inertia for one of the new half-width tanks after the bulkhead is added. Then multiply by the number of tanks to get the total. • Compare the total new moment of inertia to the original by forming a ratio (new/original). What numerical factor relates them?

✅ Before You Answer

• Be sure you are using the correct axis: about the ship’s centerline (transverse stability), not about the tank’s own centroidal axes. • Check that you correctly update the breadth (B) from 36 ft to 18 ft for each half tank after the bulkhead is added. • Confirm you multiply by the number of tanks after inserting the bulkhead, and only then compare with the original single-tank value.

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