A circuit card in a RADAR system has just...

Study

Question 1 of 20UENUtBKRYYXeCwitxrRp

A circuit card in a RADAR system has just been replaced with a spare card. You notice the voltage level at point E in Fig. 8F12 is negative 4.75 volts when the inputs are all at 5 volts. The problem is:

Back

Question 1 of 20

UENUtBKRYYXeCwitxrRp

No comments yet

Be the first to share your thoughts!

If the question has a related picture, it will appear here.

🔍 Key Concepts

• Op amp inverting / non-inverting configurations and how resistor ratios set the output voltage • How resistor values (25 K, 50 K, 100 K) affect gain and output polarity when inputs are at +5 V • What it means for an op amp to be at the rail voltage compared with a normal linear operating point

💭 Think About

• Based on a –4.75 V output with +5 V inputs, should this op amp be inverting or non-inverting, and what does that say about the sign of the gain? • Which resistor change (making a resistor larger or smaller) would make the magnitude of the (negative) output closer to or farther from the supply rail? • If the output were actually at the rail, would you expect it to be exactly –4.75 V, or closer to the full negative supply value shown in the figure?

✅ Before You Answer

• Identify whether point E is supposed to be positive or negative under normal operation when all inputs are at +5 V • Check which resistor(s) control the gain ratio that sets Vout = (gain) × Vin, and whether a wrong value would flip polarity or only change magnitude • Confirm what the negative rail voltage is in the figure (e.g., –5 V, –12 V, etc.) and compare it carefully with the –4.75 V reading

👋 Hi! I'm Genie, your AI study assistant. How can I help you with this question?

Quick actions

— No credit card needed